Open File Dialog C#

OpenFileDialog m_OpenFile = new OpenFileDialog();
m_OpenFile.Title = "Buscar Base de Datos";
m_OpenFile.Filter = "All Files(*.*)|*.*|Base de datos de Microsoft Access (*.mdb)|*.mdb";
m_OpenFile.FilterIndex = 2;
if (m_OpenFile.ShowDialog() == DialogResult.OK)
{
    txtSource.Text = m_OpenFile.FileName.ToString();
}

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